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3 years ago

What is a terminating decimal?

1 answer:

5 0

A terminating decimal has digits that end. They do not go on forever. For example, 0.125 has only 3 decimal digits and does not keep on going like 1/3

A rational number is a number that canbe expressed as p/q where p and q are both integers. But q cannot equal to 0.

All terminating decimals are rational numbers, but not all rational numbers are terminating decimals. For example 1/4, which equals to 0.25 is both a rational number and a terminating decimal. On the other hand, 1/3 is a rational number but is not a terminating decimal.

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Cuando dejamos un trozo de chocolate al sol ,se derrite

Pachacha [2.7K]

Answer:si

Step-by-step explanation:

por la calentura de sol

7 0

3 years ago

What is the length of GH¯¯¯¯¯¯, to the nearest tenth of a meter? 7.3 m 13.7 m 14.1 m 19.4 m A scalene triangle G H J. The base s

nlexa [21]

By applying the law of sines.

$\frac{GH}{sin \ J} = \frac{GJ}{sin \ H}$

Given:
GJ = 10 , ∠J =45° , ∠H = 31°

∴ $\frac{GH}{sin \ 45} = \frac{10}{sin \ 31}$

∴ GH = 10 * sin 45° / sin 31° ≈ 13.7 m

8 0

2 years ago

Read 2 more answers

naomi needs 2 cups of chopped apples for a fruit salad she is making .she only has a 1/4 cup. how many times will naomi need to

Lilit [14]

1/4 × 8 times = 2 cups
ANSWER : 8 times

5 0

3 years ago

Read 2 more answers

The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

$M=(\frac{6-2}{2},\frac{2+5}{2})$

$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

$=\sqrt{(-8)^2+(3)^2}$

$=\sqrt{64+9}$

$=\sqrt{73}$

Therefore the radius is $\sqrt{73}$

i.e., $r=\sqrt{73}$

Therefore the standard form of the circle is

$(x-h)^2+(y-k)^2=r^2$

Now substituting the center and radiuswe get

$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

5 0

2 years ago

The average annual income I in dollars of a lawyer with an age of x years is modeled with the following function I=425x^2+45,500

natali 33 [55]

You did not include the questions, but I will give you two questions related with this same statement, and so you will learn how to work with it.

Also, you made a little (but important) typo.

The right equation for the annual income is: I = - 425x^2 + 45500 - 650000

1) Determine the youngest age for which the average income of a lawyer is $450,000

=> I = 450,000 = - 425x^2 + 45,500x - 650,000

=> 425x^2 - 45,000x + 650,000 + 450,000 = 0

=> 425x^2 - 45,000x + 1,100,000 = 0

You can use the quatratic equation to solve that equation:

x = [ 45,000 +/- √ { (45,000)^2 - 4(425)(1,100,000)} ] / (2*425)

x = 38.29 and x = 67.59

So, the youngest age is 38.29 years

2) Other question is what is the maximum average annual income a layer can earn.

That means you have to find the maximum for the function - 425x^2 + 45500x - 650000

As you are in college you can use derivatives to find maxima or minima.

+> - 425*2 x + 45500 = 0

=> x = 45500 / 900 = 50.55

=> I = - 425 (50.55)^2 + 45500(50.55) - 650000 = 564,021. <--- maximum average annual income

3 0

2 years ago