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horrorfan [7]
3 years ago
12

Where should you take a lost salad

Mathematics
1 answer:
Setler [38]3 years ago
7 0
You could take it to your belly duh
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I NEED HELP ASAP! <br> Just number 8 please! Thank you
ZanzabumX [31]

Answer:

18

Step-by-step explanation:

3 0
3 years ago
4 7/8 + (-6 1/4) how do I find common denominators?
xxTIMURxx [149]
I hope this helps you

4 0
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The population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year. A) Estimate how lo
VLD [36.1K]

Answer:

A) 63.36 years.

B) 100.42 years.

Step-by-step explanation:

We have been given that the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year.

A) Since we know that population increases exponentially, therefore we will use our given information to form an exponential model for population increase and then we will solve for the time by which our population will be double.

P(t)=7.1(1.011)^{t}            

7.1 \times 2=7.1(1.011)^{t}  

\frac{7.1 \times 2}{7.1} =(1.011)^{t}

2 =(1.011)^{t}

Now let us solve for t using logarithm.

ln(2) =ln (1.011)^{t}      

ln(2) =t \cdot ln(1.011)

0.6931471805599453 =t \cdot 0.0109399400383344  

t=\frac{0.6931471805599453}{0.0109399400383344}

t=63.3593217267282743049\approx 63.36

Therefore, it will take 63.36 years the population to be double.

B) Now we will find the number of years it will take the population to be triple of its size.

7.1 \times 3=7.1(1.011)^{t}

\frac{7.1 \times 3}{7.1} =(1.011)^{t}  

3 =(1.011)^{t}

Now let us solve for t using logarithm.        

ln(3) =ln (1.011)^{t}

ln(3) =t \cdot ln(1.011)

1.0986122886681097 =t \cdot 0.0109399400383344  

t=\frac{1.0986122886681097}{0.0109399400383344}

t=100.4221490079915311298\approx 100.42

Therefore, it will take 100.42 years the population to triple of its size.


6 0
3 years ago
Mechanics paper/Math (please helpp!!!)
sp2606 [1]

Answer:

  (i) 15 m, 6 m/s

  (ii) 90 m

Step-by-step explanation:

(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...

  d = (1/2)at^2

The distance covered by Ben in the 5 seconds he is accelerating is ...

  d = (1/2)(1.2 m/s²)(5 s)² = 15 m

Of course, Ben's speed at that point is ...

  s = (1.2 m/s²)(5 s) = 6 m/s

__

(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.

It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...

  (22.5 s)(4 m/s) = 90 m . . . the distance OP

4 0
3 years ago
Find the slope of the line passing through the points (-6,7) and (-8,5)
kykrilka [37]

Answer:

Slope = 1

Step-by-step explanation:

4 0
2 years ago
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