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ki77a [65]
3 years ago
15

Francis surveyed a random sample of 707070 students at Franklin High School about their favorite season. Of the students surveye

d, 181818 chose fall as their favorite season. There are 181618161816 students at Franklin High School.Based on the data, what is the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall?
Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0

the number of students at Franklin High School whose favorite season is fall is 467

Dimas [21]3 years ago
7 0

Answer:

Approx 467 students is the answer.

Step-by-step explanation:

Francis surveyed a random sample of 70 students at Franklin High School about their favorite season.

Of the students surveyed, 18 chose fall as their favorite season.

There are 1816 students at Franklin High School.

Now, \frac{18}{70} students chose fall as their favorite season.

This comes to 0.257 percent.

We can say that 0.257 % of 1816 students can like fall season.

0.257\times1816 = 466.712 ≈ 467 students. (approx)

Therefore, the most reasonable estimate for the number of students at Franklin High School whose favorite season is fall is 467.

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3 years ago
A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes
Elena L [17]

Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

Alternative hypothesis:p < 0.38  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

3 0
3 years ago
Nick goes to the store and buys 22 notebooks for $1.50 each. Then he buys 8 pens for $0.55 each. How much money did he spend in
rosijanka [135]

Answer:

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Step-by-step explanation:

if u would multiply 33 by 1.50 you would get $33

if u would multiply 8 by 0.55 you would get $4.40

8 0
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Use the coordinates of the plotted points to complete the calculation below. Pay attention to negative signs
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answer:

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explanation

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Now, since the distance between the cars to start with is 540 km. Therefore, the time taken before the cars collide is:

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Therefore, the Canary flies flies for (100 km/h)x(3 hours) = 300 km before the cars collide.


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