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2 years ago

-2x+y=12 3x+2y=38 You have to use substitution to solve this problem

Mathematics

1 answer:

tatiyna2 years ago

5 0

{-2x+y=12 => y=12+2x

{3x+2y=38

3x+2(12+2x)=38

3x+24+4x=38 /-24

7x=14 /:7

x=2

y=12+2*2=12+4=16

y=16

Solution: (2; 16)

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3 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

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Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

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Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

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Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

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Applying the Pythagorean Theorem

Let

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$x=2\sqrt{33}\ units$

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simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

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we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

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Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

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$csc(\beta)=\frac{7}{\sqrt{33}}$

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3 years ago

HELP PLEASE FAST Solve for c. −18c=2 What is the answer? −16 −4 4 16

denpristay [2]

To solve for c, you divide both sides by -18. If you do that, your answer will be -1/16. So, I think you typed the question wrong. Pretty sure it's the first option.

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3 years ago

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