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Fantom [35]
3 years ago
13

What is the greatest 3 digit number you can subtract from 426 so that you would need to regroup?

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

419

Step-by-step explanation:

Regrouping in subtraction: If we borrow from one group (tens group) and give to another (Once group) so that the operation can be completed, then this process is called regroup.

For example: We need to find the value of 52-39

52=50+2

39=30+9

We can not subtract 9 from 2. So we will borrow 10 from 50 and give to 2.

52=40+12

Now,

52-39=(40+12)-(30+9)

52-39=(40-30)+(12-9)

52-39=(10)+(3)

52-39=13

We need to find the greatest 3 digit number that can subtract from 426 so that we need to regroup.

To use regroup, the once digit must be more that 6. So, maximum value for once place is 9.

Therefore, the greatest 3 digit number that can subtract from 426 by using regroup is 419.

kolbaska11 [484]3 years ago
6 0
Do you want me to explain it?

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What is the domain of the relation?<br><br> Express your answer using inequalities.
son4ous [18]

Answer:

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  -    -

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Two equations are given below: a – 3b = 22 a = b – 2 What is the solution to the set of equations in the form (a, b)? (–10, –8)
aliya0001 [1]
Hi Kristian

a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
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Now substitute -12 for b in a = b - 2
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The correct option is the last one (-14,-12)


If you have questions about my answer, please let me know.


Good luck! 

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