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Zepler [3.9K]
3 years ago
9

Can someone help me with these real quick?

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

1)\\p\%=\dfrac{p}{100}\\\\13\%=\dfrac{13}{100}=0.13\\\\13\%\ of\ 20\ is\ 0.13\cdot20=2.6\\\\2)\\\underbrace{7\cdot7\cdot7\cdot7\cdot7}_{5}=7^5\\\\3)\\Use:\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\12.\ 6^2\cdot6^{-4}=6^{2+(-4)}=6^{2-4}=6^{-2}\\\\13.\ 2^{-3}\cdot2^{-2}=2^{-3+(-2)}=2^{-5}\\\\14.\ \dfrac{4^4}{4^2}=4^{4-2}=4^2}\\\\15.\ \dfrac{8^3}{8^{-2}}=8^{3-(-2)}=8^{3+2}=8^5

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Answer: {(0, 2), (1, 4), (2, 6), (3, 6)}

Step-by-step explanation:

For a relation to be considered a function, each x-value needs to have one corresponding y-value--it cannot have more than 1.

Since all the other sets of ordered pairs feature points with two x-values with different y-values, the set above is the only function of the provided options.

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3 years ago
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alexgriva [62]
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Step-by-step explanation:

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I hope I helped you!

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Answer:

The answer I got was D 215605/1000

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