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3 years ago

Solve 152x = 36. Round to the nearest ten-thousandth.

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

6 0

X = 36 / 152 = 0.2368

kumpel [21]3 years ago

5 0

Since no one was getting the the answer that is on the assignment I plugged the problem into an algebra calculator, and got A 0.6616

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Hennietta has a box of fruit with a mass of 88 dekameters. What is the weight of the vid of fruit in kilograms

vagabundo [1.1K]

Answer: 0.88 kilometers

8 0

3 years ago

Read 2 more answers

Need help quickly! Thanks

Rzqust [24]

Answer:

y = $-2^x$

Step-by-step explanation:

If the equation of a function is in the form of y = h(x)

When the graph of this function is reflected across x-axis,

Transformed function will be,

y = -h(x)

Further reflected across y-axis, then the transformed function will be,

y = -h(-x)

By this rule,

Given equation when reflected across x-axis,

y = $-(\frac{1}{2})^{x}$

Further reflected across y-axis,

y = $-(\frac{1}{2})^{-x}$

y = $-(2^{-1})^x$

y = $-2^x$

5 0

3 years ago

Noelle and karina both leave the Internet cafe at the same time, but in opposite directions. If karina travels 9 mph faster than

Vesna [10]

Noelle goes east at N mph.
Karina travels west at N + 9
then their velocity between them is (N + N + 9)
After 8 hours they travel 8(2N + 9) = 232
(2N + 9) = 29
2N = 20
N = 10 mph for Noelle
N+9=19 mph for Karina

7 0

3 years ago

Explain how to write 50,000 using exponents. Answer can only be one number but the answer can have as much exponents as wanted

Oksana_A [137]

The examples of 50,000 written as an exponent are as follows (but not limited to):

500 * 10^2
50 * 10^3
5 * 10^4
0,5 * 10^5

Doublecheck (optional):

500 * 10^2 = 500 * 100 = 50,000
50 * 10^3 = 50 * 1000 = 50,000
5 * 10^4 = 5 * 10000 = 50,000
0,5 * 10^5 = 0,5 * 100000 = 50,000

5 0

3 years ago