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Mazyrski [523]
3 years ago
6

Solve 152x = 36. Round to the nearest ten-thousandth.

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0
X = 36 / 152 = 0.2368
kumpel [21]3 years ago
5 0

Since no one was getting the the answer that is on the assignment I plugged  the problem into an algebra calculator, and got A 0.6616

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
Hennietta has a box of fruit with a mass of 88 dekameters. What is the weight of the vid of fruit in kilograms
vagabundo [1.1K]

Answer: 0.88 kilometers

8 0
3 years ago
Read 2 more answers
Need help quickly! Thanks
Rzqust [24]

Answer:

y = -2^x

Step-by-step explanation:

If the equation of a function is in the form of y = h(x)

When the graph of this function is reflected across x-axis,

Transformed function will be,

y = -h(x)

Further reflected across y-axis, then the transformed function will be,

y = -h(-x)

By this rule,

Given equation when reflected across x-axis,

y = -(\frac{1}{2})^{x}

Further reflected across y-axis,

y = -(\frac{1}{2})^{-x}

y = -(2^{-1})^x

y = -2^x

5 0
3 years ago
Noelle and karina both leave the Internet cafe at the same time, but in opposite directions. If karina travels 9 mph faster than
Vesna [10]
Noelle goes east at N mph.
Karina travels west at N + 9
then their velocity between them is (N + N + 9)
After 8 hours they travel 8(2N + 9) = 232
(2N + 9) = 29
2N = 20
N = 10 mph for Noelle
N+9=19 mph for Karina

7 0
3 years ago
Explain how to write 50,000 using exponents. Answer can only be one number but the answer can have as much exponents as wanted
Oksana_A [137]
The examples of 50,000 written as an exponent are as follows (but not limited to):

500 * 10^2
50 * 10^3
5 * 10^4
0,5 * 10^5

Doublecheck (optional):

500 * 10^2 = 500 * 100 = 50,000
50 * 10^3 = 50 * 1000 = 50,000
5 * 10^4 = 5 * 10000 = 50,000
0,5 * 10^5 = 0,5 * 100000 = 50,000
5 0
3 years ago
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