Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
0 is the only degree that cannot work
Answer:
0.47x + 7.72
Step-by-step explanation:
We have to create a Linear model using the given two points on the graph. The two points are: (21, 17.5) and (43, 2.75)
The general equation of the line in slope intercept form is
y = mx + c
where m is the slope and c is the y-intercept.
Calculating the slope:

Using the value of m in above equation we get:
y = 0.47x + c
Calculating the y-intercept:
Using any of the given points we can calculate the value of c. Using the point (21, 17.5) in the above equation, we get:
17.5 = 0.47(21) + c
c = 17.5 - 0.47(21)
c = 7.63
Therefore, the equation is:
y = 0.47x + 7.63
Hence option a is the correct answer. The slight change in the value of "c" is because of rounding the value of m to 2 decimal places.
So from the given options, the correct answers is:
y = 0.47x + 7.72
We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
<span>
<span>
<span>
we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
</span> </span>
Source:
http://www.1728.org/mixture.htm