Internal combustion energy for TNT(Trinitro toluene) is found to be -170 kJ.
Internal energy= (- heat evolved by the system) + Work done by the system
ΔU = -Q+W
W = - PΔV
P= pressure
ΔV =difference in volume
Given,
V1 = 10 L
V2 = 90 L
∴ΔV = V2-V1 = 90-10 = 80 L
P = 1 atm
∴W = - ( 1× 80)
= -80 kJ
Heat evolved by the system = 90 kJ
∴Δ U= - 90 kJ - 80 kJ
= - 170 kJ
Thus, Internal combustion energy for TNT(Trinitro toluene) is found to be -170 kJ.
NOTE : here work done by the system is considered negative and also heat evolved by the system is taken -Ve.
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[Co(NH₃)₅Br]²⁺
Ligands and charges on them,
5 × NH₃ = 5 × 0 = 0
1 × Br⁻¹ = 1 × -1 = -1
Charge on sphere = +2
So, putting values in equation,
Co + (0)₅ - 1 = +2
Co + 0 - 1 = +2
Co - 1 = +2
Co = +2 + 1
Co = +3
Result:
Oxidation state of Co in [Co(NH₃)₅Br]²⁺ is +3.
B. 133.88
Sorry po kung mali
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
<span>solution of KI becomes saturated at 10 degrees when around 135-138g KI are added to 100 g of water, so it should be still unsaturated, A. unsaturated (although it is very close to saturation)</span>
