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Vikki [24]
2 years ago
11

I need help pls Where does it belong to?​

Chemistry
1 answer:
Daniel [21]2 years ago
6 0
The answer is B. Fungi,Protists
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I’ve been up all night doin chemistry, can someone please give me the answers
m_a_m_a [10]
Here are your answers:

1. MgBr2 + Cl2 = MgCl2 + Br2

Balancing,
Already balanced.

Type of reaction: single displacement


2. Al + Fe2O3 = Al2O3 + Fe

Balancing,
2Al + Fe2O3 = Al2O3 + 2Fe

Type: single displacement reaction


3. AgNO3 + ZnCl2 = AgCl + N2O6Zn

Balancing,
2AgNO3 + ZnCl2 = 2AgCl + N2O6Zn

Type: double displacement reaction

MnO2
4. H2O2 ====== O2 + H20 [being catalyzed by manganese dioxide]

Balancing,
MnO2
2H2O2 ====== O2 + 2H2O

Type: decomposition reaction


5. Zn + HCl = ZnCl2 + H2

Balancing,
Zn + 2HCl = ZnCl2 + H2

Type: single displacement reaction


6. H2SO4 + NaOH = Na2SO4 + H2O

Balancing,
H2SO4 + 2NaOH = Na2SO4 + 2H2O

Type: Acid-base reaction




That took hella long!!! Hope it helps.
4 0
3 years ago
Why is the time series useful as a management tool?
katrin [286]

Answer:

A)

Explanation:

It estimates the probability of extinction.

8 0
3 years ago
plz help me asap (plz don't give me helpless answer plz and ty) and also ill give brainist to the person that work hard
Vesna [10]
Question? I don’t see anything
8 0
2 years ago
What is the change in the freezing point of water when 35.0 g of sucrose is
frez [133]

From the calculations, we can see that, the change in the freezing point is -0.634°C.

<h3>What is freezing point?</h3>

The term freezing point refers to the temperature at which a liquid is changed to solid.

Given that;

ΔT = K  m i

Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles

molality =  0.1 moles/ 300.0 * 10^-3 Kg

= 0.33 m

Thus;

ΔT = -1.86°C/mol *  0.33 m * 1

= -0.634°C

Learn more about freezing point:brainly.com/question/3121416

#SPJ1

3 0
2 years ago
Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium
Eddi Din [679]

Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

So, number of moles of NaOH = Volume × Molarity

                                                   = 71.0 ml × 0.760 M

                                                    = 0.05396 mol

Also, moles of  CH_{3}COOH = moles of CH_{3}COONa

                                          = Molarity × Volume

                                          = 1.00 M × 1.00 L

                                          = 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

            CH_{3}COONa + NaOH \rightarrow CH_{3}COOH

Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

               = 4.74 +  log \frac{0.94604}{1.05396}

               = 4.69

Therefore, change in pH will be calculated as follows.

                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

8 0
3 years ago
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