Answer:
F = K Q1 * Q2 / R^2 force between 2 charged particles
F2 / F1 = R1^2 / R2^2 = (R1 / R2)^2 = (R1 / R1 /2)^2 = 2^2 = 4
d) the force would be increased by a factor of 4
53....................................
Explanation:
Answer:
The answers to your questions are given below
Explanation:
22. The energy of an electromagnetic wave and it's frequency are related by the following equation:
E = hf
Where:
E => is the energy
h => is the Planck's constant
f => is the frequency
From the equation i.e E = hf, we can conclude that the energy of a wave is directly proportional to it's frequency. This implies that an increase in the frequency of the wave will lead to an increase in the energy of the wave and also, a decrease in the frequency will lead to a decrease in the energy of the wave.
23. Gamma ray and radio wave are both electromagnetic waves. All electromagnetic waves has a constant speed of 3×10⁸ m/s in space.
Thus, gamma ray and radio wave have the same speed in space.
The impulse is (force) x (time) = (20 N) x (20 sec) = 400 N-sec
When we grind through the units, we find that the [newton-second]
is exactly the same as the [kilogram-meter/sec] unit-wise, and once
we know that, it doesn't surprise us to learn that impulse is equivalent
to a change in momentum (mass x speed ... also kg-m/s).
So this impulse exerted on the moving object adds 400 kg-m/s of
linear momentum to its motion, directed to the right. That may or
may not be the total change in its momentum during that 20-sec,
because our 20-N may not be the only force acting on it.
