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iris [78.8K]
3 years ago
5

Which fact about the moon, as seen from the earth, is evidence that the amount of time the Moon takes to complete one rotation a

nd one revolution are nearly identical?
a.We usually see the Moon at night.
b.We cannot see the Moon on some nights.
c.We always see the same side of the Moon from Earth.
d.We only see a “Full Moon” for a day or two per lunar cycle.
Physics
2 answers:
Cerrena [4.2K]3 years ago
6 0
Choice ' c ' is the evidence.
kirill115 [55]3 years ago
6 0

Answer:  C) We always see the same side of the Moon from Earth

Explanation:    

                       The moon is a natural satellite of earth which orbits around the earth with an orbital period (time to complete one revolution ) of around 27 days . Along with this the moon also rotates about its own axis with period of rotation 27 days which is approximately same as the period of revolution . Due to this coincidence that the amount of time the Moon takes to complete one rotation and one revolution are nearly identical , we always see the same side of the Moon from Earth .

           If the Moon did not rotate on itself or did so at a different rate, it would gradually show its entire surface: the visible side and the hidden side. The coincidence between both periods (the rotation and orbital periods) is known as synchronous rotation.

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Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocid
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Answer:

Velocidad final, V = 40 m/s

Explanation:

Dados los siguientes datos;

Aceleración = 5 m/s²

Velocidad inicial = 0 m/s (ya que comienza desde el reposo)

Tiempo = 8 segundos

Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;

V = U + at

Dónde;

  • V es la velocidad final.
  • U es la velocidad inicial.
  • a es la aceleración.
  • t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

V = 0 + 5*8

V = 0 + 40

V = 40

<em>Velocidad final, V = 40 m/s</em>

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3 years ago
During normal beating, the heart creates a maximum 4.00-mV potential across 0.300 m of a person’s chest, creating a 1.00-Hz elec
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Answer:

(a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

Explanation:

Given that,

Maximum potential = 4.00 mV

Distance = 0.300\ m

Frequency = 1.00 Hz

(a). We need to calculate the maximum electric field strength

Using formula of the potential difference

\Delta V=Ed

E=\dfrac{\Delta V}{d}

E=\dfrac{4.00\times10^{-3}}{0.300}

E=0.0133\ V/m

(b). We need to calculate the maximum magnetic field strength in the electromagnetic wave

Using formula of the maximum magnetic field strength in the electromagnetic wave

B=\dfrac{E}{c}

Put the value into the formula

B=\dfrac{0.0133}{3\times10^{8}}

B=4.433\times10^{-11}\ T

(c). We need to calculate the wavelength of the electromagnetic wave

Using formula of wavelength

c=f\lambda

\lambda=\dfrac{c}{f}

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{1.00}

\lambda=3\times10^{8}\ m

Hence, (a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

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