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Vinil7 [7]
2 years ago
13

Which of the following is NOT a vector quantity?

Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
3 0

B.

A star is not a vector quantity.

Neither is temperature.

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a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v​
sesenic [268]

Here

  • Acceleration and initial velocities are constant.

According to first equation of kinematics.

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+at

\\ \sf\longmapsto v=at

\\ \sf\longmapsto v\propto t

  • Time was t at velocity v
  • Time will be 4t at velocity 4v
7 0
3 years ago
What’s the meaning of physics??
lukranit [14]

Answer:the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

Explanation:

7 0
3 years ago
A force of 100 newtons was necessary to lift a rock. a total of 150 joules of work was done. how far was the rock lifted
Makovka662 [10]

Answer:

1.5m

Explanation:

150÷100=1.5

Work done ÷force

4 0
3 years ago
A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13
salantis [7]

The work done by the applied force = 650 J

Given the mass of the box = 40 kg

The displacement of the box on applying force = 5 m

Applied horizontal force = 130 N

The co-efficient of friction between box and floor is = 0.3

We have to find the work done by the applied force.

Work done by the applied force = Applied Force x Displacement of the box

                                                      = 130 N x 5 m

                                                      = 650 J

[Here the unit Nm is known as Joule(J) ]

We have the co-efficient of friction. So,

The force applied due to friction = Mass of the box x Co-efficient of friction                                                                   x Acceleration due to gravity

                                                      = 40 kg x 0.3 x 9.8

                                                      = 117.6 N

Learn more about Work done at brainly.com/question/62183

#SPJ4

6 0
1 year ago
Suppose the Sun appeared to you 900 times dimmer than it does now. How far away from the Sun would you be? (A) 1/9 AU (B) 3 AU
Harrizon [31]

Answer:

The correct answer is option 'c': 30 AUs

Explanation:

For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

e=\frac{E}{4\pi r^{2}}

This energy per unit area is sensed by observer as intensity of the sun.

Let the initial intensity of sun at a distance r_{1} be e_{1}

Thus if the sun becomes 900 times dimmer we have

e'=\frac{e_{1}}{900}\\\\\frac{E}{4\pi r_{2}^{2}}=\frac{1}{900}\times \frac{E}{4\pi r_{1}^{2}}\\\\\Rightarrow r_{2}^{2}={r_{1}^{2}}\times 900\\\\\therefore r_{2}={r_{1}}\times {30}

Thus the distance increases 30 times.

5 0
3 years ago
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