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Vinil7 [7]
2 years ago
13

Which of the following is NOT a vector quantity?

Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
3 0

B.

A star is not a vector quantity.

Neither is temperature.

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Which is an example of a physical change
mote1985 [20]
Water boiling is an example of a physical change. The rest are chemical changes.  
Hope that helps!!
6 0
3 years ago
what will happen to the brightness of the other bulbs in a series circuit if any of the bulbs were to burn out?
Ivenika [448]

Answer:

not work.

Explanation:

if u are saying in a series circuit...

if 1 build burns out and theres other bulbs the circuit wont work anymore.

6 0
3 years ago
A 0.050 kg bullet strikes a 5.0 kg wooden block with a velocity of 909 m/s and embeds itself in the block which fies off its sta
serg [7]

Answer:

The final velocity of the bullet is 9 m/s.

Explanation:

We have,

Mass of a bullet is, m = 0.05 kg

Mass of wooden block is, M = 5 kg

Initial speed of bullet, v = 909 m/s

The bullet embeds itself in the block which flies off its stand. Let V is the final velocity of the bullet. The this case, momentum of the system remains conserved. So,

mv=(m+M)V\\\\V=\dfrac{mv}{m+M}\\\\V=\dfrac{0.05\times 909}{0.050+5}\\\\V=9\ m/s

So, the final velocity of the bullet is 9 m/s.

5 0
3 years ago
Mangrove forests play an important role in _______.
AysviL [449]
D. All of the above

At high tide fish will feed among the mangrove roots - rich fishing ground

The trees trap sediment and soil in the river that would flow out to sea which also helps stop erosion

Wildlife utilise almost every part of the tree, with insects and birds, monkeys and lizards in the branches, shrimps and fish in the roots, and snails and clams in the soil
4 0
2 years ago
A sled of mass m is coasting on the icy surface of a frozen river. While it is passing under a bridge, a package of equal mass m
sweet [91]

Answer:B

Explanation:

Given

mass of Sled is m

another package of mass m is thrown on it

Suppose u be the initial velocity of sled

conserving momentum

mu=2mv

v=\frac{u}{2}

where v is the final velocity

Initial kinetic energy =\frac{1}{2}mu^2

Final Kinetic Energy=\frac{1}{2}(2m)\cdot (\frac{u}{2})^2

Final Kinetic Energy=\frac{1}{2}\times \frac{1}{2}mu^2

Final kinetic Energy is half of initial    

5 0
3 years ago
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