Amygdala helps in processing emotions
I hope I could answer part of your question
Answer:
Coin is dropped from a height of 19.62 m
Explanation:
We have given time t = 2 sec
As coin is drop means its initial velocity u = 0 m/sec
We have to find the height from which coin is dropped
From second equation of motion we know that

So height 
So coin is dropped from a height of 19.62 m
<u>False</u>
<u>Explanation:</u>
Most of us have a belief that Earth is very close to the sun in summer season and so it is hotter. Also, since Earth is far away from the sun in winter season, it is colder. Though this idea looks true, it is incorrect.
The orbit of the Earth isn't a perfect circle. It is quite tilted. During some months of the year, Earth is very close to the sun than at other times. We have winter when the Earth is very close to the sun and summer when it is far away in the Northern Hemisphere. So when we compare the distance of the Sun from the Earth, this change in Earth's distance throughout the year does not affect our weather much.
Answer: 14139.19 m
Explanation:
This situation is related to parabolic motion and can be solved using the following equations:
(1)
(2)
Where:
is the horizontal distance (where the artillery shell lands)
is the initial velocity
is the angle
is the time
is the final height
is the initial height
is the acceleration due gravity, always directed downwards
So, let's begin by isolating
from (2):
(3)
(4)
Substituting (4) in (1):
(5)
Rewriting (5) and taking into account
:
(6)
(7)
Finally:
Given Information:
v = 3.5x10⁵ m/s
θ = 60°
Magnetic field = 0.60 T
no. of electrons = 6.242x10¹⁸
radius = 0.750 m
Required Information:
Magnetic force = F = ?
Magnetic field = B = ?
Answer:
Part A) F = 2.909x10⁻¹⁴ N
Part B) B = 5.34x10⁻⁷ T
Explanation:
Part A:
The magnetic force can be found using
F = qvBsin(θ)
Where q = 1.60x10⁻¹⁹ C and v is the speed of electron, B is the magnetic field and θ is the angle between v and B.
F = 1.60x10⁻¹⁹*3.5x10⁵*0.60sin(60°)
F = 2.909x10⁻¹⁴ N
Part B:
From the Ampere's law, the magnetic field can be found using
B = μ₀I/2πr
Where μ₀ = 4πx10⁻⁷ is the permeability of free space, I is the current, and B is the magnitude of the magnetic field produced.
1 ampere of current has 6.242x10¹⁸ electrons per second so
I = 1.25x10¹⁹/6.242x10¹⁸
I = 2.0032 A
B = 4πx10⁻⁷*2.0032/2π*0.750
B = 5.34x10⁻⁷ T