Simplify the polynomial by using foil or box method (2y-1)(y+4)

Fernanda has a collection of 200 seashells from corpus christi she gage her sister one-fifth of her collection how many seashell

8090 [49]

1/5 of 200 is 40 which mean she gave 40 away and she has a 160 left

7 0

3 years ago

Which expression is not equivalent to

Zanzabum

Answer:

A

Step-by-step explanation:

Because 6^3/6^6 is equivalent to 1/216.A is 1/36

8 0

3 years ago

Read 2 more answers

Find the LCM of this set of numbers. 5 and 25

Andrej [43]

Answer:

25

Step-by-step explanation:

LCM = Least Common Multiple

To find the LCM, start by listing multiples, or the product of any two numbers.

5: 5, 10, 15, 20, 25, 30, 35...

25: 25, 50, 75, 100, 125, 150, 175...

Now, let's find the LCM by selecting the smallest shared multiple out of the lists we made.

5: 5, 10, 15, 20, 25, 30, 35...

25: 25, 50, 75, 100, 125, 150, 175...

Therefore, 25 is the LCM of 5 and 25.

4 0

3 years ago

What is the total number of students in the dataset?

Allushta [10]

total number of student in the data set in the dataset is 90

5 0

3 years ago

Read 2 more answers

D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she

Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:

$\frac{i}{e}=\frac{5}{3}$

Let's multiply both sides by e. This yields:

$i=\frac{5}{3}e$

We know that when the income is increased by 5000 and the expenditures are decreased by 3000, the new ratio is 5:2. So, we can write the following proportion:

$\frac{i+5000}{e-3000}=\frac{5}{2}$

Let's multiply both sides by $(e-3000)$ :

$i+5000=\frac{5}{2}(e-3000)$

Since we know that $i=\frac{5}{3}e$ , substitute:

$\frac{5}{3}e+5000=\frac{5}{2}(e-3000)$

So, let's solve for the expenditures. Distribute the right:

$\frac{5}{3}e+5000=\frac{5}{2}e-7500$

Subtract $\frac{5}{2}e$ from both sides:

$-\frac{5}{6}e+5000=-7500$

Subtract 5000 from both sides:

$-\frac{5}{6}e=-12500$

Multiply both sides by -6/5. So, the expenditures are:

$e=\text{Rs }15000$

We can use the original ratio to find Sunayana's income:

$i=\frac{5}{3}e$

Substitute 15000 for e. Evaluate:

$i=\frac{5}{3}(15000)=\text{Rs }25000$

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

3 0

3 years ago

Read 2 more answers