They both contain the point B, also B is the vertex of angle EBF or FBE
Answer:
3x9+3x8+1
x9
Step-by-step explanation:
x−10x+3−(−3x−2)(x)
=
3x12+3x11+x3
x12
The distance from the base of the tree to the tallest would be 14.21 cm
<h3>We have the following data points in this question</h3>
X1 = 8 feet
y1 = 16 feet
x2 = 11 feet
y2 = 9 feet
To proceed with the solution we have to
We have to solve for the shorter tree
<em>= </em>9² + 11²
= √81 +121
= 14.21
<h3>For the taller tree we would have</h3>
√8² + 16²
= √64 +256
= 17.89
Read more on distance here:
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Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.
Answer:
y=76 degree(being vertically opposite angle)
y+x=180 degree(being linear pair)
76+x=180
x=180-76
x=104 degree
x=z(being vertically opposite angle)
104=z
therefore z=104 ,y=76,x=104
Step-by-step explanation:
