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2 years ago

What is the equation of the line that passes

Mathematics

1 answer:

Afina-wow [57]2 years ago

4 0

Answer:

Step-by-step explanation:

First, find the slope of the line for the two points.

Slope is Rise/Run.

For the two points (-8,-4) and (3,-10):

Rise (-10 - (-4)) = -6

Run (3 - ( -8)) = 11

The slope is Rise/Run or -(6/11)

The equation becomes y = -(6/11)x + b

Find b by entering either of the 2 points given. I'll use (3,-10):

y = -(6/11)x + b

-10 = -(6/11)(3) + b

b = -10 + (6/11)(3)

b = -10 +(18/11)

b = -(110/11) + (18/11)

b = -(92/11)

The equation becomes y = -(6/11)x - (92/11)

See attached graph.

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) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

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Answer:

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Step-by-step explanation:

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