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ludmilkaskok [199]
3 years ago
10

Rey was planning a party and made a candy bowl with 4 Snickers bars, 2 Hersey’s bar, and 5 Twix bars.

Mathematics
1 answer:
quester [9]3 years ago
3 0

Step-by-step explanation:

a /100%

b/0%

c/5/11 or 45% or 44%

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A bank manager wants to encourage new customers to open accounts with principals of at least $3,000. He decides to make a poster
ankoles [38]

Assuming that the 4.8% interest rate is an annual interest rate, then, after one year, with a principal of $3,000 we would be able to win 4.8% of $3000:

3000\times\frac{4.8}{100}=144

Divide 144 over 12 to find the monthly earnings:

\frac{144}{12}=12

Therefore, with a principal of $3,000 we would be earning $12 interest in 1 month.

For the earnings on the first month to be equal to $10, then you would have to win $120 annually, and $120 must be 4.8% of the principal. To find which quantity satisfies that 4.8% of it is equal to $120, divide 120 over 4.8%:

\frac{120}{4.8\text{ \%}}=\frac{120}{(4.8/100)}=\frac{100}{4.8}\times120=2500

Therefore, the principal must be equal to $2500 for you to win $10 on the first month, and it would indeed be correct to say that if you open an account with $3000 you will earn at least $10 interest in 1 month.

7 0
1 year ago
Dan has ¾ of a cake left over from his birthday party. His best friend Amy ate 1/7 of the leftover cake. How much of the cake do
Dafna1 [17]

Answer:

  • 9/14 of cake left

Step-by-step explanation:

<u>3/4 left and 1/7 of that eaten:</u>

  • 3/4 - 3/4(1/7) =
  • (3/4) (1 - 1/7) =
  • (3/4)(6/7) =
  • 18/28 =
  • 9/14

4 0
3 years ago
Read 2 more answers
Solve the math problem
k0ka [10]

If this is an option, it should be Similar Triangles.

3 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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