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Oduvanchick [21]

3 years ago

14

What are the x and y-intercepts of the line described by the equation?

2 answers:

STatiana [176]3 years ago

8 0

To find the x int, sub in 0 for y and solve for x
3x - 9y = 10.8
3x - 9(0) = 10.8
3x = 10.8
x = 10.8/3
x = 3.6 or (3.6,0) <== ur x int

to find the y int, sub in 0 for x and solve for y
3x - 9y = 10.8
3(0) - 9y = 10.8
-9y = 10.8
y = -10.8/9
y = - 1.2 or (0,-1.2) <== ur y int

vekshin13 years ago

3 0

Answer:

x=3.6

y=1.2

Step-by-step explanation:

add me

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Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 500, \pi = \frac{421}{500} = 0.842$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874$

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0

3 years ago

Solve The Equation -3x+7=-2

Svetradugi [14.3K]

Subtract 7 from -2 and 7 since 7 is currently a positive number

Your equation should now look like this:

-3x=-9

Next you have to divide by 3 on each side to get:

X=3

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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The product of 3 and a number is at most nine

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