The solution is the interval b is in ]11.3, infinity[
Solving this inequality:
-6>t-(-13)
solve as an equation;
6>t+13
6-13>t
-7>t
-7 is greater than t, which means that can be any number smaller that t, fir instance -8, -22 etc.
2% , 5% , 10% are the errors in that
Answer:
10 -16 i
Step-by-step explanation:
given,
(3+ 4 i) + (7 − 20 i)
for the given complex number
if the number is added of subtracted the real part will add or subtract to the real part and imaginary will add or subtract to the imaginary part.
now
= (3+ 4 i) + (7 − 20 i)
= (3 + 7) + (4+(-20)) i
= 10 + (-16) i
= 10 -16 i
so, the given answer will be 10 -16 i
9514 1404 393
Answer:
sin(∅) = -√65/65
Step-by-step explanation:
The identities that relate the cotangent, the cosecant, and the sine are ...
csc² = 1 +cot²
sin = 1/csc
_____
For the given values, we find ...
csc(∅)² = 1 +cot(∅)² = 1 +8² = 65
csc(∅) = -√65 . . . . . . . . . . . . . . . . square root with attention to sign
sin(∅) = -1/√65 = (-√65)/65
