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prohojiy [21]
3 years ago
8

Can someone help with these 2 problems?

Mathematics
1 answer:
AysviL [449]3 years ago
8 0
Question 11 is C and also question 2 is A
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Simplify the expression where possible.<br><br> (-5 x 2 ) 3 help please!
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The answer to (-5 × 2) 3 = -30.
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A farm stand sold 12 ears of corn for $4. The farm stand sold 180 ears of corn at the same rate.
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Divide 4 by 12, which equals approximately 0.33333, then multiply that to 180, which gives us 60. So she sold 180 ears of corn for $60.
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3 years ago
Read 2 more answers
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

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3 years ago
A group of 2 adults and 4 children pay $95 for admission to a water park. A
il63 [147K]

Answer:

2a + 4c = 95

3a +7c =155

Step-by-step explanation:

2a + 4c = 95

3a +7c =155

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3 years ago
Using the graph, select an answer.
saul85 [17]

Answer:

there's no graph??

Step-by-step explanation:

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