All categories

3 years ago

Relying on windows and building materials to capture incoming solar radiation WITHOUT distributing that energy is called:

Physics

2 answers:

andre [41]3 years ago

6 0

Answer:

Option (B)

Explanation:

<u>Passive solar heating refers to the process in which the incoming solar radiations are being allowed to enter a room through the doors and windows, and are trapped within the walls of the rooms and building materials, which are later converted into electrical energy</u>.

It is a very cheap and efficient method and causes no harm to the environment like the other energy sources such as radioactive energy and fossil fuel energy.

Thus, the correct answer is option (B).

eimsori [14]3 years ago

5 0

The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>Relying on windows and building materials to capture incoming solar radiation WITHOUT distributing that energy is called: passive solar heating.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

You might be interested in

An ideal Diesel cycle has a compression ratio of 18 and a cutoff ratio of 1.5. Determine the (1) maximum air temperature and (2)

weqwewe [10]

Answer:

(1) The maximum air temperature is 1383.002 K

(2) The rate of heat addition is 215.5 kW

Explanation:

T₁ = 17 + 273.15 = 290.15

$\frac{T_2}{T_1} =r_v^{k - 1} =18^{0.4} =3.17767$

T₂ = 290.15 × 3.17767 = 922.00139

$\frac{T_3}{T_2} =\frac{v_3}{v_2} = r_c = 1.5$

Therefore,

T₃ = T₂×1.5 = 922.00139 × 1.5 = 1383.002 K

The maximum air temperature = T₃ = 1383.002 K

(2)

$\frac{v_4}{v_3} =\frac{v_4}{v_2} \times \frac{v_2}{v_3} = \frac{v_1}{v_2} \times \frac{v_2}{v_3} = 18 \times \frac{1}{1.5} = 12$

$\frac{T_3}{T_4} =(\frac{v_4}{v_3} )^{k-1} = 12^{0.4} = 2.702$

Therefore;

$T_4 = \frac{1383.002}{2.702} =511.859 \ k$

$Q_1 = c_p(T_3-T_2)$

Q₁ = 1.005(1383.002 - 922.00139) = 463.306 kJ/jg

Heat rejected per kilogram is given by the following relation;

$c_v(T_4-T_1)$ = 0.718×(511.859 - 290.15) = 159.187 kJ/kg

The efficiency is given by the following relation;

$\eta = 1-\frac{\beta ^{k}-1}{\left (\beta -1 \right )r_{v}^{k-1}}$

Where:

β = Cut off ratio

Plugging in the values, we get;

$\eta = 1-\frac{1.5 ^{1.4}-1}{\left (1.5 -1 \right )18^{1.4-1}}= 0.5191$

Therefore;

$\eta = \frac{\sum Q}{Q_1}$

$\therefore 0.5191 = \frac{150}{Q_1}$

Heat supplied = $\frac{150}{0.5191} = 288.978 \ hp$

Therefore, heat supplied = 215491.064 W

Heat supplied ≈ 215.5 kW

The rate of heat addition = 215.5 kW.

7 0

4 years ago

A 1300 kg car starts at rest and rolls down a hill from a height of 10.0 m. It then moves across a

Makovka662 [10]

Answer:

0.51 m

Explanation:

Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.

Kinetic energy, KE=½kx²

Where k is spring constant and x is the compression of spring

Potential energy, PE=mgh

Where g is acceleration due to gravity, h is height and m is mass

Equating KE=PE

mgh=½kx²

Making x the subject of formula

$x=\sqrt {\frac {2mgh}{k}}$

Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then

$x=\sqrt \frac {2*1300*9.81*10}{1000000}=0.50503465227646m\\x\approx 0.51 m$

5 0

3 years ago

Please help?? PWEASE PWEASE PWEASE

elixir [45]

Answer:

draw the two atomic structures and then focus in on the electrons either gaining or losing and draw them with arrows and dots

Explanation:

3 0

3 years ago

An engineer is investigating energy loss through windows. The windowpane of interest is 0.650 cm thick, has dimensions of 1.19 m

krok68 [10]

Answer:

7908.92307 W

683330953.248 J

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = $1.19\times 2.25\ m^2$

l = Thickness = 0.65 cm

$T_2$ = 24°C

$T_1$ = 0°C

Rate of heat transfer is given by

$Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 1.19\times 2.25(24-0)}{0.65\times 10^{-2}}\\\Rightarrow Q=7908.92307\ W$

The rate of heat transfer is 7908.92307 W

Amount of energy is given by

$E=Qt\\\Rightarrow E=7908.92307\times 24\times 3600\\\Rightarrow E=683330953.248\ J$

The energy transferred through the window in one day is 683330953.248 J

8 0

3 years ago

Using dimensional analysis, show that energy can be calculated from the following energy equations. Hint, in SI, here we want Jo

anyanavicka [17]

Explanation:

1. The kinetic energy of any object is calculated as :

$E=\dfrac{1}{2}mv^2$ ...........(1)

Dimensional formula of energy, $[E]=[ML^2T^{-2}]$

Dimensional formula of mass is $[M]$

Dimensional formula of velocity, $[v]=[LT^{-1}]$

$[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2$

So, $[ML^2T^{-2}]=[ML^2T^{-2}]$

LHS = RHS

2. The potential energy is given by :

$E=mgh$

Dimensional formula of mass is $[M]$

Dimensional formula of g is $[LT^{-2}]$

Dimensional formula of height is $[L]$

Dimensional formula of energy, $[E]=[ML^2T^{-2}]$

So, $E=[M][LT^{-2}][L]$

So, LHS = RHS

Hence, this is the required solution.

7 0

3 years ago