Explanation:
1. The kinetic energy of any object is calculated as :
...........(1)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of velocity, ![[v]=[LT^{-1}]](https://tex.z-dn.net/?f=%5Bv%5D%3D%5BLT%5E%7B-1%7D%5D)
![[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5Cdfrac%7B1%7D%7B2%7D%5BM%5D%28%5BLT%5E%7B-1%7D%5D%29%5E2)
So, ![[ML^2T^{-2}]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
LHS = RHS
2. The potential energy is given by :

Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of g is ![[LT^{-2}]](https://tex.z-dn.net/?f=%5BLT%5E%7B-2%7D%5D)
Dimensional formula of height is ![[L]](https://tex.z-dn.net/?f=%5BL%5D)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
So, ![E=[M][LT^{-2}][L]](https://tex.z-dn.net/?f=E%3D%5BM%5D%5BLT%5E%7B-2%7D%5D%5BL%5D)
So, LHS = RHS
Hence, this is the required solution.