The highest number that both 9 and 27 can be multiplied into is 9. 9 can go into 9 one time, and 9 can go into 27 three times.
9•1=9
9•3=27
(9, 18, 27 )=times
I hope I helped.
Step-by-step explanation:
Given that,
BC = 8
Ac = 15
We can find AB using the pythagoas theorem.

We know that,
, B is base and H is Hypotenuse

Hence, this is the required solution.
Answer:
-45
Step-by-step explanation:
put x = -6 and y=3 in this expression : y(2x - y)
3(2(-6)-3) = 3(-12 -3)= 3(-15) = -45
Take the logarithm of both sides. The base of the logarithm doesn't matter.


Drop the exponents:

Expand the right side:

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :


Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

You can stop there, or continue simplifying the solution by using properties of logarithms:



You can condense the solution further using the change-of-base identity,

Answer:
16:12 or 4:3
Step-by-step explanation:
Girls + boys = 28
Girls + 12 = 28
Girls = 16
Girls to boys:
16:12
16/12
4:3