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irinina [24]
4 years ago
9

Use the electron configurations and the periodic table to answer the questions: A series of five short lines. The first has an u

p and a down arrow, and is labeled below 1 s. The second has an up and a down arrow, and is labeled 2 s. The third has an up arrow and no label. The fourth has an up arrow and is labeled 2 p. The fifth has an up arrow and no label. Which element is this?
Chemistry
2 answers:
castortr0y [4]4 years ago
6 0

Answer:

Nitrogen (N) for the first answer. Bromine (Br) for the second.

Explanation:

Literally just did it on Edge!

ikadub [295]4 years ago
4 0

Answer:

Nitrogen (N) on Edge20

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Answer:

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Calculate the [OH-] and the pH of 0.035 M KOH.
DanielleElmas [232]

Answer:

pH

= 12.54

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Explanation:

KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1

In any aqueous solution, the H3O+ and OH - must satisfy the following condition -

[ H_3O^+] [OH^-] = k_w

[ H_3O^+] = \frac{k_w}{ [OH^-]}

[H_3O^+]  = \frac{1 * 10^{-14}}{3.5 *10^{-2}[H_3O^+]  = 2.857 * 10^{-13} M

pH =

- log [ H_3O^+]\\- log [2.857 * 10^{-13}]

pH

= - [-12.54]\\= 12.54

pOH = 14 - pH

pOH

= 14 - 12.54\\= 1.46

OH concentration = antilog 1.46

OH- concentration 28.84

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