Answer:
T final = 80°C
Explanation:
∴ Q = 18000 cal
∴ m H2O = 300 g
∴ Cp H2O (15°C) = 0.99795 cal/g.K ≅ 1 cal/g.K
∴ T1 = 20°C = 293 K
∴ T2 = ?
⇒ 18000 cal = (300 g)(1 cal/g.K)(T2 - 293 K)
⇒ (18000 cal)/(300 cal/K) = T2 - 293 K
⇒ T2 = 293 K + 60 K
⇒ T2 = 353 K (80°C)
The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.
Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.
Alkanes are further divided into three more types which are:
1. Chain alkanes
2. Cycloalkanes
3. Branched alkanes
Hydrogenation method is used for preparation of alkanes from alkene and alkyne.
The names of the given compounds are:
Part A:
2,2- dimethyl butane
Part B:
2,4- dimethyl hexane
Part C:
2,2,3,3- tetramethyl butane
Part D:
4- ethyl, 3,6- dimethyl heptane
Learn more about alkanes from the link given below.
brainly.com/question/16837399
#SPJ1
Answer:D.
Explanation:i used photo math. It is really helpful when I'm doing math homework etc...
