Answer:
False ....
first of all gas is not the desirable product of combustion
Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
540g
Explanation:
Given parameters:
Mass of the aluminium oxide = 1020g
Unknown:
Mass of aluminium = ?
Solution:
To find the mass of the aluminium formed from this reaction, we work from the known to the unknown. The known here is the mass of the aluminium oxide.
Using this mass, find the number of moles in the aluminium and relate it using the balanced equation to that of the unknown aluminium.
From the number of moles, we can easily find the mass of the aluminium.
Solving:
Balanced equation:
2Al₂O₃ → 4Al + 3O₂
Number of moles of Al₂O₃ = 
Molar mass of Al₂O₃ = 2(27) + 3(16) = 102g/mol
Number of moles =
= 10mol
From the balanced equation:
2 moles of Al₂O₃ produced 4 moles of Al
10 moles of Al will produce
= 20moles of Al
Mass of Al = number of moles of Al x molar mass of Al = 20 x 27 = 540g
Learn more:
Number of moles brainly.com/question/13064292
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Answer:
20L is the new volume
Explanation:
In this case, moles and T° from the gas remain constant. This is the formula we must apply, to solve this:
P₁ . V₁ = P₂ . V₂
5 atm . 10 L = P₂ . 2.5L
P₂ = (5 atm . 10 L) / 2.5L →20L
Kinetic energy is the correct answer for this question