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coldgirl [10]
3 years ago
11

An ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T, what would be the change

in pressure (P)?
Chemistry
2 answers:
Olin [163]3 years ago
6 0
According to Gayle Lusac's law, pressure is proportional to absolute temperature of a gas. Thus:
P/T = constant

So if the temperature becomes 3T, the pressure would increase to 3P
KengaRu [80]3 years ago
6 0
It will increase to 3P. 

I hoped I helped and if you need more you can always ask me :)
-Dawn
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Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;
marishachu [46]

<u>Answer:</u> Pairs are:  (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

  • <u>For a:</u>

The given electronic configuration is:  1s^22s^22p^63s^2

The number of valence electrons in the given configuration are 2

  • <u>For b:</u>

The given electronic configuration is:  1s^22s^22p^63s^3

The number of valence electrons in the given configuration are [2 + 3] = 5

  • <u>For c:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^64s^23d^{10}4p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For d:</u>

The given electronic configuration is:  1s^22s^2

The number of valence electrons in the given configuration are 2

  • <u>For e:</u>

The given electronic configuration is:  1s^22s^22p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For f:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^3

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are:  (a) and (d), (b) and (f), (c) and (e)

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Answer : The correct option is B- Towards the left.

Solution : Given,

Force on car in upward direction, F_1 = 6000 N

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Force on car in left direction, F_4 = 6000 N

Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.

Formula :  F =  m × a

where, F is force, m is mass and a is acceleration.

From the given diagram we conclude that the F_1 and F_2 are in opposite direction and the force acting on car are same. So, their net force is zero.

And in case of F_3 and F_4, the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because F_4 is higher than the F_3.

So, the car will accelerate towards left direction.


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