Answer:
我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈
Explanation:
我實際上不知道答案,我只是為了點我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈數而這樣做,哈哈,祝你好運哈哈
Answer:
Explanation:
Hello there!
In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:
Regards!
1. Berkelium(Berkeley, CA) 2. Dubnium(Dubna, Russia) 3. Darmstaditum (Darmstadt, Germany) 4. Erbium(Ytterby, Sweden) 5. Strontium(Strontian, Scotland) 6. Terbium(Ytterby, Sweden) 7. Yttebium(Ytterby, Sweden) 8. Yttrium(Ytterby, Sweden)
Answer:
Explanation:
Hello,
Based on the given undergoing chemical reaction is is rewritten below:
By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:
Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:
Best regards.