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Mademuasel [1]
4 years ago
14

Calculate the molecular weight when a gas at 25.0 ∘C and 752 mmHg has a density of 1.053 g/L . Express your answer using three s

ignificant figures.
Chemistry
1 answer:
stiks02 [169]4 years ago
7 0

Answer:

26.0 g/mol is the molar mass of the gas

Explanation:

We have to combine density data with the Ideal Gases Law equation to solve this:

P . V = n . R .T

Let's convert the pressure mmHg to atm by a rule of three:

760 mmHg ____ 1 atm

752 mmHg ____ (752 . 1)/760 =  0.989 atm

In density we know that 1 L, occupies 1.053 grams of gas, but we don't know the moles.

Moles = Mass / molar mass.

We can replace density data as this in the equation:

0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K

(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x

0.0405 mol = 1.053 g / x

x =  1.053 g / 0.0405  mol = 26 g/mol

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4 years ago
Read 2 more answers
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Llana [10]

Answer:

See explanation

Explanation:

a. I can conclusively tell if the crown was made of gold by measuring its density. First the mass of the crown is measured on a weighing balance. The crown is now put into a given volume of water and the volume of water displaced is accurately measured. The density of the crown is computed as mass/volume of fluid displaced. If the density of the crown is 19.3 g/mL, then it is made of solid gold.

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5 0
3 years ago
How many molecules are in 3.0 moles of O2
Alex777 [14]
Answer:  " <span>1.8 * 10²⁴ molecules of O₂ " .
________________________________________</span>

3.0 moles O₂ * (6.02 * 10²³ molecules O₂ / 1 mol O₂) = 


[ (3.0) *(6.02 * 10²³) ] molecules O₂
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______________________________________________________
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3 years ago
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4 years ago
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alexira [117]

Answer:

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Explanation:

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I hope you find this information useful and interesting! Good luck!

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