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stellarik [79]
3 years ago
15

If f(x) = ||x|| , find f (-1/4)

Mathematics
1 answer:
spin [16.1K]3 years ago
8 0
Anything that is absolute value is just that same number

therefore the answer is 1/4

hope this helps
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The Cost of producing n items is given as C = 5 + 2n, where 5 is initial cost and 2 is a cost per item. Profit is given as P = 3
aleksandrvk [35]
P=5 and initial to the 3 price
4 0
3 years ago
The number of hours a typical student spends per week at school has an Order of Magnitude of 1.
Margarita [4]
If the number of hours in school each week is somewhere between 20 and 40, then it can be written in scientific notation as
  2.0×10¹ to 4.0×10¹

The exponent of 10 in each case is 1, so we can say the Order of Magnitude is 1.
  TRUE


_____
In Engineering terms, the order of magnitude is sometimes considered to be the integer part of the base-10 logarithm of the number.
  log(20) ≈ 1.3010
  log(40) ≈ 1.6021
If we round these numbers to integers, we find the order of magnitude of the first is 1; the order of magnitude of the second is 2. Thus a student who spends 6 hours per day for 5 weekdays in class will have hours with an order of magnitude of 1, while a student who spends 7 hours per day for 5 days each week will have hours with an order of magnitude of 2. This question is best answered by considering "order of magnitude" in the simplistic terms of the answer above: the exponent of 10 in scientific notation.
8 0
3 years ago
Your cost is $250.you increase by 125%.what is the selling price?
Vitek1552 [10]
The answer is $312.50
8 0
3 years ago
A scientist has 2/3 of liter of solution. He uses 1/2 of the solution of the solution for an experiment.
Ede4ka [16]
Remember,
To subtract 2/3-1/2 you have to make them equivalent
2/3×2-1/2×3 = 4/6 - 3/6=
1/6
3 0
3 years ago
Read 2 more answers
Subtract: 6/2x^+8x - x/4x^+12x-16 = 6/2x(x+4) - x/4(x+4)(x-1) = 6•2(x-1)/2x(x+4)•2(x-1) - x•x/4(x+4)(x-1)•x
ss7ja [257]

Answer:

$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$

Step-by-step explanation:

$\frac{6}{2x(x+4)}- \frac{x}{4(x+4)(x-1)} $

$\frac{6\cdot2(x-1)}{2x(x+4)\cdot2(x-1)}- \frac{x\cdot x}{4(x+4)(x-1)x} $

$\frac{12(x-1)}{4x(x+4)(x-1)}- \frac{x^2}{4x(x+4)(x-1)} $

$\frac{12(x-1)-x^2}{4x(x+4)(x-1)}$

$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$

5 0
4 years ago
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