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OleMash [197]
4 years ago
14

What unit would you use to measure the weight of a flea?

Mathematics
2 answers:
Ierofanga [76]4 years ago
6 0
A. Milligrams 
Hope this helps!
zhuklara [117]4 years ago
6 0
You would use '(A) mg' because that is the smallest unit of measurement, from the ones listed, thus it will give the highest resolution.

Hope this helps! :)
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What is the equivalent sum to 2556 over 5000 ???? Idk if u get it
scoray [572]
If over you mean division then it would be 2556 divided by 5000 and that would equal 0.5112 and if you meant it to be addition because sum means the answer of an addition problem then it would be 7556 because of 2556 plus 5000, but i dont know if that is what you meant by your question. if you explain the lesson to me that you are learning, then i might be of more help to you in solving your problem.
4 0
3 years ago
Please I need help!!!!!!
8090 [49]

Answer:

What? I'm in middle school ;-;

Step-by-step explanation:


8 0
3 years ago
Find the area of the trapezoid by decomposing it into other shapes.
dimulka [17.4K]

Answer:

In the question the person was asking

Step-by-step explanation:

It says area= 80.5. Try it and I promise you all it will be right.

5 0
3 years ago
Merritt is driving to Mount Shasta. On her map, she is a distance of 7 3/4 inches away. The scale of the map is 1/2 inch = 50 mi
Over [174]
387.5 miles. because, if 1/2=0.50 then let's make that 0.50 into 1.00. and let's divide 7 3/4 by 2 because, you multiplied 0.50 by 2. 7 3/4=3.875 then multiply by 100=387.5 

if you have any trouble just ask my in the comments

3 0
4 years ago
Read 2 more answers
3^(x-2) = 5^(x+1)
Molodets [167]

Answer:

x=log_{\frac{3}{5} }(45)

x-2=log_{3}(5)x+log_{3}(5)  \\x-log_{3}(5)x=log_{3}(5)+2\\(1-log_{3}(5))x=log_{3}(5)+2\\x=\frac{log_{3}(5)+2}{1-log_{3}(5)} \\x=\frac{log_{3}(5)+log_{3}(3^2)}{log_{3}(3)-log_{3}(5)} \\x=\frac{log_{3}(5x3^2)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(5x9)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(45)}{log_{3}(\frac{3}{5} )}\\x=log_{\frac{3}{5}}(45)

Hope this helps you :)

8 0
3 years ago
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