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3 years ago

Army

Mathematics

2 answers:

Ksju [112]3 years ago

8 0

Answer:

43.2

Step-by-step explanation:

I took the test

ser-zykov [4K]3 years ago

5 0

Answer:

97.2°

Step-by-step explanation:

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The Right Answer Only You will get Reported if its wrong!!!!!

vekshin1

Answer:

Step-by-step explanation:

I found the angle by taking the opposite side of the angle, 38, and dividing it by the hypotenuse, 53.

Then I used the inverse sine function on 38/53 to get the angle 45.81, which I rounded to 46.

7 0

2 years ago

Read 2 more answers

Gabriel invested $77,000 in an account paying an interest rate of 3%

const2013 [10]

Answer:

Isabella earn $5604.54$ more money than Gabriel

Step-by-step explanation:

As we know

Compound interest (CI) $= P (1 + \frac{r}{n})^{nt}$

P is the principal amount

t is the time period

n is the number of time periods

r is the rate of interest

a) CI for Gabriel

$= 77000 (1 + \frac{3}{100*12})^{12*6}$ $= 92165.03$ dollars

b) CI for Isabella

$= 77000 (1 + \frac{4}{100*4})^{4*6}$ $= 97769.57$ dollars

Isabella earn $5604.54$ more money than Gabriel

7 0

2 years ago

Simplify 3^2/3.3^1/5

san4es73 [151]

ANSWER:

$\frac{1}{5} \\$

EXPLANATION:

$\frac{ \frac{{3}^{2}}{3 \times{3}^{1}}}{5} = \\$

$\frac{ \frac{9}{3 \times 3} }{5} = \\$

$\frac{ \frac{9}{9} }{5} = \\$

$\frac{1}{5} \\$

4 0

3 years ago

Of the choices below, what is the best estimate of the speed of the milk van?

galben [10]

Answer:

A. 77 kilometers per hour

Step-by-step explanation:

Speeds of vehicles are normally calculated in kilometers per hour, meters per hour is too small the measurement and millimeters is even smaller.

7 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago