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Stolb23 [73]
3 years ago
10

Plz help me with this

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

4 n - 7

Step-by-step explanation:

- 3 , 1 , 5 , 9

The difference between the terms is 4, so our multiplier is 4 n

4 , 8 , 12 , 16 ( The 4 times tables )

-3 , 1 , 5 , 9 ( The original sequence )

What are we doing to get from the 4 times tables to get to the original sequence?

4 - - 3 = 7

8 - 1 = 7

12 - 5 = 7

16 - 9 = 7

We are subtracting 7 so our complete general term is 4 n -7

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Consider the function f(x)=3x-1 (over)x+4 (a) At which value of x will the function not have a solution? Explain your answer. (b
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Ans(a):

Given function is f(x)=\frac{3x-1}{x+4}

we know that any rational function is not defined when denominator is 0 so that means denominator x+4 can't be 0

so let's solve

x+4≠0 for x

x≠0-4

x≠-4

Hence at x=4, function can't have solution.


Ans(b):

We know that vertical shift occurs when we add something on the right side of function so vertical shift by 4 units means add 4 to f(x)

so we get:

g(x)=f(x)+4

g(x)=\frac{3x-1}{x+4}+4

We may simplify this equation but that is not compulsory.

Comparision:  

Graph of g(x) will be just 4 unit upward than graph of f(x).


Ans(e):

To find value of x when g(x)=8, just plug g(x)=8 in previous equation

8=\frac{3x-1}{x+4}+4


8-4=\frac{3x-1}{x+4}


4=\frac{3x-1}{x+4}


4(x+4)=(3x-1)


4x+16=3x-1


4x-3x=-1-16

x=-17

Hence final answer is x=-17

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