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3 years ago

2 to the -6 power in expotional form and simplified in fractions

Mathematics

2 answers:

IceJOKER [234]3 years ago

4 0

Answer:

1/64

Step-by-step explanation:

$2 ^{ - 6}$

$1 \div 2 ^{6}$

$1 \div 64$

Furkat [3]3 years ago

4 0

Answer:

0.015625

and

1/64

Step-by-step explanation:

those r the answers

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Solve the equation 8x squared - 4 =28

Yuri [45]

8x² - 4 = 28
8x² = 28 + 4
8x² = 32
x² = 32/8
x² = 4
x = <span>±2

</span>

4 0

4 years ago

Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.

denpristay [2]

Answer: 9

Step-by-step explanation:

Given

The function is $x^2-6x+c$

To make it a perfect square, compare it with $(a-b)^2=a^2+b^2-2ab$

Here,

$x=a,\\-6x=-2ab\\\\\therefore b=3$

So, c must be square of b i.e. 9

$x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2$

Therefore, value of c is 9.

3 0

3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago

Please solve quickly!!

tamaranim1 [39]

Answer:ya

Step-by-step explanation:

explanation idk

6 0

3 years ago

What is the measure of one interior angle of a regular polygon that has 40 sides?

s344n2d4d5 [400]

Hope this is correct and hope it helps x

8 0

3 years ago