Answer:
23 ,21,10,63,13
Explanation:
We have to convert binary to decimal
10111 corresponding decimal number is
10101 corresponding decimal number is
01010 corresponding decimal number is
111111 corresponding decimal number is
001111 corresponding decimal number is
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
Yessirrr like 3 times a week
Answer:
Explanation:
i think he alive but in heaven i dunno
Answer:
//Code is created using java
import java.util.*;
// returns the sum
public int sum(int N)
{
if(N==1)
return (1);
else
return N+sum(N-1);
}
// code to return the Bipower ouput
public int BiPower(int N)
{
if(N==1)
return (2);
else
return 2*BiPower(N-1);
}
// Code to return TimesFive output
public int TimesFive(int N)
{
if(N==1)
return 5;
else
return 5 + timesFive(N-1);
}
public static void main(String args[])
{
//Prompts the user to enter a nonnegative integer
int N = Integer.parseInt.(console.readLine("Enter a nonnegative integer: "));
//Outputs the sum, Bipower and TimesFive
System.out.println(sum(n));
System.out.println(BiPower(n));
System.out.println(TimesFive(n));
}
}
