All categories

3 years ago

What is the coefficient of (-2/3x)(3y)(-2x)

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

The coefficient is equal to $4$

Step-by-step explanation:

we have

$(-\frac{2}{3}x)(3y)(-2x)$

we know that

The coefficient is equal to

$(-\frac{2}{3})(3)(-2)=4$

$(-\frac{2}{3}x)(3y)(-2x)=4x^{2}y$

You might be interested in

18.3: Sand Wagon

12345 [234]

Answer:

702/9 is 78 your answer is 78

Step-by-step explanation:

27*13*2

3 0

3 years ago

My teacher is asking for me to do the math of 5.05 + = 13.25, then convert to a fraction. I don't know how to do that.

Alenkasestr [34]

Answer:

5.05 + x=13.25

x=8.20

=82/10

41/5

Step-by-step explanation:

3 0

2 years ago

In exercises 1 and 2, find m<1 and m<2. Tell which theorem you used in each case.

solniwko [45]

Answer:

m∠2 = 78°

Step-by-step explanation:

From the given picture,

lines 'm' and 'n' are the parallel lines and line 't' is the transverse line.

∠1 and angle with the measure of 78° are corresponding angles.

Therefore, m∠1 = 78°

m∠1 = m∠2 [Vertical angles are equal]

m∠2 = 78°

8 0

2 years ago

I am not sure if this is right can someone check it ASAP please

NikAS [45]

Answer:

x=10

Step-by-step explanation:

3(4x-12) = 84

Divide each side by 3

3/3(4x-12) = 84/3

4x-12 =28

Add 12 to each side

4x-12+12 = 28+12

4x= 40

Divide each side by 4

4x/4 = 40/4

x = 10

6 0

3 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago