Question

Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions?
10x2 - 19x + 6 = 0

-19 ± 11
19 ± 11
19 ± 12

Answer 1

10x2 - 19x + 6 = 0

a=10, b=-19 c, =6

Quadratic Formula: x = [ -b (+-) sqrt(b^2 - 4ac) ] / 2a

x=19(+ -) sqrt(-19^2-4*10*6)/2*10

Answer would be (19 ± 11)/20

pls check your answer ,in your options denominator 20 is missing