Answer:
7
Step-by-step explanation:
Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors
"
Find all the squared values that lies between 360 and 630
360< 19², 20², 21², 22², 23², 24², 25² < 630
19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.
answer: 4.8
A. -1
(1,2) and (2,1)
slope = 2 -1 / 1 -2
slope = 1 / -1
slope = -1
Answer:
-18
Step-by-step explanation:
You can basically just drop the plus sign and remove the parenthesis because the plus sign doesn't alter negatives.
-6+(-12)
-6-12= -18
Answer:
Step-by-step explanation:
