First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
<em>AB = 3π</em>
Step-by-step explanation:
<em>See attachment for correct format of question.</em>
Given
From the attachment, we have that
θ = 20°
Radius, r = 27
Required
Find length of AB
AB is an arc and it's length can be calculated using arc length formula.
<em>Substitute 20 for θ and 27 for r</em>
Hence, the length of arc AB is terms of π is 3π
Answer:
The solution for x that I got is 7.6.
When substituted for x for the two equations, the angle measures are:
86, 38.4, and 55.6.
86 degrees is the largest angle measure.
Answer:
Can you teach me coeffeicients please honestly like you I need help on the
question to I don't blame you for having trouble on this questions
Answer:
(n/3)-10=6
Step-by-step explanation:
Let n be the number
Quotient of n and 3 is n/3
10 less that this is (n/3)-10=6
