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3 years ago

9

Please guys! I have ONE more question left. I AM GIVING 15 POINTS. PLEASE ANSWER! THANK YOU!

1 answer:

Ivahew [28]3 years ago

4 0

Boy, that's easy. Its 209= 14x+y.

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How many 1/3 cups of ice cream can you make from 1/7 cup

OlgaM077 [116]

Well first you have to make the denominators equal by finding a common denominator. in this case 21, but whatever you do to the bottom you do to the top. so 1/3 times 7/7 equals 7/21 and 1/7 times 3/3 equals 3/21.

so how many 7/21 cups of ice cream can you make from 3/21 i think about none but remember i could be wrong

8 0

3 years ago

Which statement about the value of x is true?

klemol [59]

X=2 I believe it is

7 0

3 years ago

What transformation is described by the

spayn [35]

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that I can think of.

8 0

3 years ago

Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago

Simplify the the expression <br> (4x^4y)^2*2x^3y^4

Elden [556K]

Answer: 32x^11 y^6

If you are still confused just let me know i will do it step by step :)

4 0

3 years ago