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Lera25 [3.4K]
3 years ago
9

Please guys! I have ONE more question left. I AM GIVING 15 POINTS. PLEASE ANSWER! THANK YOU!

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0

Boy, that's easy. Its 209= 14x+y.

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Does anyone know what the code is Ive been stuck on this for like ever.
timama [110]

Answer:

Binary code

Step-by-step explanation:

Code is a word or a symbol which is not disclosed to everyone and is considered as secretive. There are various codes which are required to run a software in order to minimize the risk of piracy. These codes are binary codes or java codes. These are complex so that not everyone can crack it.

3 0
3 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
3 years ago
if you invest $4,000 in an account that earns 3% interest. How much will you have in the account in 10 years?
Dmitrij [34]

Answer:

18,000

Step-by-step explanation:

4 0
3 years ago
ANSWER ASAP ILL MARK BRAINLIEST!!!
KonstantinChe [14]

Answer:

1/4 , -17/4)   (0,-4)

Step-by-step explanation:

I used my brain

5 0
3 years ago
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Pls help on this question ​
sveticcg [70]

Answer:

178.571429

Step-by-step explanation:

Area of square - 10*10 m = 100m

Area of the semicircle = Diameter = 10m, so the radius = 5m

Area of circle = \pi r^{2}

=> Area = 22/7 * 25

=> 78.5714286

Area of figure = 78.5714286 + 100 = 178.571429

Hope it helps :)

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3 years ago
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