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Georgia [21]
2 years ago
12

Determine the equation whose roots are –1 –5 and –3

Mathematics
1 answer:
Alexus [3.1K]2 years ago
5 0
Well you are given the roots.

if we have 3 it would.have to be x^3. So something like:

y = ax^3 + bx^2 + cx + d

this could.also be written:

y = (x + a) (x + b) (x + c)

when you are able to write it like this, we know that the opposite of a, b, and c are roots. this is because if we can make any of the insides of the 3 parenthesis equal 0 then y = 0 and that x.is a root. Well if we know the 3 roots that x will be then we just have to figure out the a, b, and c. So let's plug our roots in.

y = (-1 + a) (-5 + b) (-3 + c)

now we have to make each parenthesis equal 0 to find what a, b, and c should be. It is obvious a = 1 to make.that one zero and b = 5 and c = 3. So we know a, b, and c. now let's plug.those into our first equation.

y = (x + 1) (x + 5) (x + 3)

this is your equation. You can multiply out if necessary
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The product of 2 more than a number and 10 is 36 more than 8 times the number. What is the number?
kati45 [8]

Here's my step-by-step explanation:

Whenever you see the phrase "a number" in a problem like this, then they want you to use a variable. Let's use <em>n</em> for number and translate from English to Algebraic.

- The product of 2 more than a number and 10 is 36 more than 8 times the number.

- The product of 2 more than <em>n</em> and 10 is 36 more than 8 times <em>n.</em>

<em>- </em>The product of 2 + <em>n</em> and 10 is 36 + 8<em>n.</em>

<em>- </em>(2 + <em>n</em>)(10) is 36 + 8<em>n.</em>

<em>- </em>(2 + <em>n</em>)(10) = 36 + 8<em>n</em>

Let's solve.

(2 + <em>n</em>)(10) = 36 + 8<em>n</em>

20 + 10<em>n</em> = 36 + 8<em>n</em>

10<em>n</em> - 8<em>n</em> = 36 - 20

2<em>n</em> = 16

<em>n</em> = 8

Hope this helps, let me know if I made a mistake or if you have any questions!

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Step-by-step explanation:

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