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max2010maxim [7]

3 years ago

10

The following graph is f(x) = sin(x), true or false?

2 answers:

timurjin [86]3 years ago

7 0

The answer is true

Hope this helped :)

Andreyy893 years ago

4 0

True. It passes through the origin, so it's the sine function (rather than the cosine function).

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

7) Mary wants to make several cans that have a radius of 3 and height of 5. She is going to cut them from a sheet of metal that

kati45 [8]

Answer:

5

Step-by-step explanation:

7 0

3 years ago

14,6,-2,...;27th term

Pavel [41]

Answer:

27th term = -194

Step-by-step explanation:

The terms decrease by 8.

3 0

3 years ago

Darya [45]

Answer:

Step-by-step explanation:

7 0

1 year ago

Find the values of m for which the lines y=mx-2 are tangents to the curve with equation y=x^2-4x+2

deff fn [24]

Let y= mx-2 be the tangent line to y=x^2-4x+2 at x=a.

Then slope, $m=\frac{dy}{dx} at x=a = 2a-4.$

Hence the equation is y=(2a-4)x-2

Let's find y-coordinate at x=a using tangent line and curve.

Using tangent line y at x=a is (2a-4) a -2 $=2a^{2}-4a-2$

Using given curve y-coordinate at x=a is $a^{2}-4a+2$

Let's equate these 2 y-coordinates,

$2a^{2} -4a-2 = a^{2} -4a+2$

$2a^{2}-a^{2} = 2+2$

$a^{2}=4$

a=2 or -2.

If a=2, $m=2a-4 = 2*2-4=0$

If a=-2, $m= 2(-2)-4 = -8$

Hence m values are 0 and -8.

8 0

3 years ago