3 years ago

What is the vertex of the graph of the equation y= 3x^2+6x+1

1 answer:

8 0

$y=a(x-h)^2+k \Rightarrow \hbox{vertex}=(h,k)\\y= 3x^2+6x+1\\ y=3x^2+6x+3-2\\ y=3(x^2+2x+1)-2\\ y=3(x+1)^2-2\Rightarrow h=-1,k=-2\\\\ (-1,-2)$

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