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elixir [45]
3 years ago
13

Homework: Wk 3 Homework - Updated

Mathematics
1 answer:
Amanda [17]3 years ago
5 0
A regular triangle has a side length
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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

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nadezda [96]

Answer:

The answer is c. (0,-1)

Step-by-step explanation:

So the unit circle is derived from a right triangle.

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Answer:

im getting 148,400 as the answer

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Answer:

Step-by-step explanation:

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standard form is Ax+By=C.

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