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posledela
3 years ago
15

Evaluate the expression when m= 6 and n= 64.

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

What's the expression?

Step-by-step explanation:

You didn't attach the expression anywhere.

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Help please. I'm stuck.
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  15

Step-by-step explanation:

Each bracelet takes 28+10 = 38 elastic bands. If you have 600 bands, you can make ...

  600/38 = 15 30/38 . . . bracelets

You can make 15 complete bracelets.

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A lotion is made from an oil blend costing $1.50 per ounce and glycerin costing $1.00 per ounce. Four
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Motorola used the normal distribution to determine the probability of defects and the number
vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z

Total defects=Production*Probability

                      =0.3174*1000

                       =317.4

b. \mu=10,\sigma=0.05

therefore:-

z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z

Defects=Probability*Production

            =0.0026*1000

             =2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

3 0
3 years ago
A jar consists of blue, red and green marbles. The probability of each of them is 2/7 , 3/k and 5/2k. Find the value of k.
jok3333 [9.3K]

Answer:

k = 77/10

Step-by-step explanation:

The jar consist of blue, red and green marbles . The probability of each of them can be described as follows.

probability of blue marbles = 2/7

probability of red marbles = 3/k

probability of green marbles = 5/2k

The sum of the individual probability is equals to 1. Therefore,

2/7 + 3/k + 5/2k = 1

collect like terms

(6 + 5)/2k = 1 - 2/7

11/2k =(7 - 2) /7

11/2k = 5/7

cross multiply

10k = 77

divide both sides by 10

k = 77/10

6 0
3 years ago
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