According to reliable sources online, the FICA rate last 2010 amounted to 6.2%. The amount deducted to Eleanor's pay monthly is calculated by multiplying the monthly pay and the rate. That is,
FICA (monthly) = ($2,478.15)(0.062)
= $153.636
Multiplying that amount by 12 (since there are 12 months in a year) is equal to $1843.632. Thus, $1843.632 was deducted from Eleanor's pay last 2010 for FICA.
Answer:
a) Figure attached
b) For this case we want this probability:

And we can use the complement rule:

And we can use the cumulative distribution function given by:

And replacing we got:

Step-by-step explanation:
For this case we define the random variable X= depth (in centimeters) of the bioturbation layer in sediment for a certain region, and we know the distribution for X, given by:

Part a
For this case we can see the figure attached.
Part b
For this case we want this probability:

And we can use the complement rule:

And we can use the cumulative distribution function given by:

And replacing we got:

Answer:
the answer is the same as it is.
I believe the correct answer is 6.4.
.033333
3/100
Hopes this helps! :)