Answer:
There are 42 quarters (and 6 dimes).
Step-by-step explanation:
The given ratio is 2:14. But this does not tell us how many dimes nor how many quarters we have. Instead, it's a ratio. Modify this by multiplying numerator and denominator by n and then find n:
Number of dimes 2n
----------------------------- = -----
Number of quarters 14n
Then the total number of coins is 2n + 14n =48, implying that:
16n = 48, or n = 3.
Then the number of dimes is 2(n) = 2(3) = 6, and that of quarters is 14(n) =
14(3) = 42.
There are 42 quarters (and 6 dimes). Notice how the total of 42 and 6 is 48.
The volume of the geometry that is oblique prism is
. Then the correct option is A.
<h3>What is Geometry?</h3>
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
Given
The oblique prism below has an isosceles right triangle base.
The triangular bases have 2 sides with a length of x.
The distance from the 2 triangular bases is (x + 3).
The vertical height of the prism is (x + 2).
The volume of the oblique prism will be
![\rm Volume = Area\ of \ triangle * Vertical\ Height \\\\Volume = \dfrac{1}{2} (Base)^2 * Vertical \ Hetght\\\\Volume = \dfrac{1}{2} x^2 (x + 2)\\\\Volume = \dfrac{1}{2} x^3 + x^{2} \\\\](https://tex.z-dn.net/?f=%5Crm%20Volume%20%3D%20Area%5C%20of%20%5C%20triangle%20%2A%20Vertical%5C%20Height%20%5C%5C%5C%5CVolume%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20%28Base%29%5E2%20%2A%20Vertical%20%5C%20Hetght%5C%5C%5C%5CVolume%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20x%5E2%20%28x%20%2B%202%29%5C%5C%5C%5CVolume%20%3D%20%20%5Cdfrac%7B1%7D%7B2%7D%20x%5E3%20%2B%20x%5E%7B2%7D%20%5C%5C%5C%5C)
The volume of the oblique prism is
.
Thus, option A is correct.
More about the geometry link is given below.
brainly.com/question/7558603
$25. 25 x 3 is 75. Plus the 100 is 175. 200 - 175 is $25
Answer: Abby- Marvel
Step-by-step explanation:
Just way better and deeper plotline in my personal opinion.
Answer:
Step-by-step explanation:
First, you gotta work out the hypotenuse of ABC, which is AC.
To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.
12.5/5 = 2.5
The scale factor length between the two triangles is 2.5.
You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.
Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB
Pythagoras's theorem = ![a^2 + b^2 = c^2](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%20%3D%20c%5E2)
a = BC = 12.5
b = AB = we need to work this out
c = AC (the hypotenuse we just worked out) = 32.5
Let's both simplify and rearrange this at the same time so that we have our b on one side.
= 1056.25 - 156.25
b = ![\sqrt{(1056.25 - 156.25)}](https://tex.z-dn.net/?f=%5Csqrt%7B%281056.25%20-%20156.25%29%7D)
b = ![\sqrt{900}](https://tex.z-dn.net/?f=%5Csqrt%7B900%7D)
b = AB = 30 We've found b or AB, now we can work out the perimeter of ABC.
Perimeter of ABC = AB + BC + AC
= 30 + 12.5 + 32.5
= 75 Here's the perimeter for ABC.