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loris [4]
3 years ago
9

What is an equation for the linear function whose graph contains the points (9, 7) and (4, −8) ?

Mathematics
1 answer:
aalyn [17]3 years ago
5 0
Y=mx+b where m=slope which is change in y divided by change in x                 m=(-8-7)/(4-9)=-15/-5=3 so we have                                                                 y=3x+b now we can use either point, I'll use (9,7), to solve for b or the y-intercept...                                                                                                         7=3(9)+b                                                                                                           7=27+b                                                                                                         b=-20so our line is:                                                                                              y=3x-20


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I hope this helps

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2. In the circle shown, secants PE and PF have been drawn such that mCE  82 , mDF  98 and the ratio 3. In circle O, tangent
Andrew [12]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The arc PR is  \theta _{PR}  = 84

Step-by-step explanation:

A descriptive diagram of the diagram given in the question is shown on the first uploaded image

  In the circle tangent  \=  {M \= Q} , secant PE and  chord PF are drawn

given that  \theta _ {MPQ} = 102^o , \theta _{M} =  60^o

   The objective is to determine PR

From the diagram we see that MQ is a straight which implies that the the angle

      \theta_{NPM}  =  180 -102

      \theta_{NPM}  =  78^o

Now looking at triangle NMP we see that

          \theta _{MNP} =  180  -[ \theta_{NMP} + \theta _{NPM}]

         \theta _{MNP} =  180  - [60 + 78 ]

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 So with the knowledge

   Then

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  Looking at the diagram we see that

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             42 = \frac{1}{2}  \theta _{PR}

              \theta _{PR}  = 2  *  42

               \theta _{PR}  = 84

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