<em>Greetings from Brasil...</em>
In a trigonometric function
F(X) = ±UD ± A.COS(Px + LR)
UD - move the graph to Up or Down (+ = up | - = down)
A - amplitude
P - period (period = 2π/P)
LR - move the graph to Left or Right (+ = left | - = right)
So:
A) F(X) = COS(X + 1)
standard cosine graph with 1 unit shift to the left
B) F(X) = COS(X) - 1 = -1 + COS(X)
standard cosine graph with 1 unit down
C) F(X) = COS(X - 1)
standard cosine graph with shift 1 unit to the right
D) F(X) = SEN(X - 1)
standard Sine graph with shift 1 unit to the right
Observing the graph we notice the sine function shifted 1 unit to the right, then
<h3>Option D</h3>
<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>
Answer:
S = 2
Step-by-step explanation:
1st step: Simplify both sides of the equation
4/5 s - 3/4 s = 1/10
4/5 s + -3/4 s = 1/10
(4/5 s + -3/4 s) = 1/10 (combine like terms)
1/20 s = 1/10
1/20 s = 1/10
step 2: multiply both sides by 20
20 * (1/20 s) = 20 * (1/10)
s = 2
Hope this helped!
For this case we must solve a system of two equations with two unknowns, given by "x" and "y".
We have:
We multiply (2) by -1:
We add (1) and (3):
Clearing x:
We substitute in (2)
Thus, the solution of the system is
Answer:
The solution of the system is
Answer:y=-2/1x+12
Step-by-step explanation:
To find slope you need to use slope formula (y2-y1)/(x2-x1)
(2-4)/(5-4)
-2/1 is our slope
Now we need the y-int
Y=-2/1x+b
Take one of the given points and apply it to our equation
2=-2/1(5)+b
2=-10/1+b
2=-10+b
Add 10 to each side
12=b
Our final equation is
y=-2/1x+12