Which of the following is an irrational number?4/3 , ^24, ^81, -4.07

1 answer:

6 0

Well lets start by narrowing the answers.
You can't have a fraction as a irrational number so even though 4/3= 1 1/2 its still not an irrational number.
Negative 4.07 also can't be an irrational number because an irrational number is a number that never ends and even thought irrational numbers can be written as decimals -4.07 is not an irrational number.
I don't really want to give u the answer but I did limit ur choices so hope that helps!!!

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Use a translator or whatever, just don't know how to do it. Will give most helpful answer brainliest, with an explanation and an

bekas [8.4K]

The answer is -60. this is because the signs implemented in front of numbers give it a sort pattern .

when there are two additions the last number after the positive sign will give a positive number 1 greater than the initial number for example + 5 + 6. Answer afterward will be + 7 and for negative sign eg: - 7 - 8 in the question will give the answer -8 the same number after a negative (-) sign .
Hope this helps

4 0

2 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$