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zhenek [66]
3 years ago
13

SNOG PLEASE HELP ME! (a+5)(b-3)

Mathematics
2 answers:
Bingel [31]3 years ago
8 0

Answer:

ab-3a+5b-15

Step-by-step explanation:

Once again, FOIL is the way to go!

First, Outside, Inside, Last

ab-3a+5b-15

soldi70 [24.7K]3 years ago
7 0

Answer:

apply de disruptive property by multiplying each term a+5by each term b-3

ab - 3a + 5b - 15

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iogann1982 [59]
49 I think I might be wrong
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3 years ago
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(r, 7), (11, 8), m = -1/5
soldier1979 [14.2K]

Answer:

The value of r is 16

Step-by-step explanation:

<u><em>The correct question is</em></u>

Find out the value of r if the slope between the two ordered pairs is m=-1/5

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points

(r, 7), (11, 8)

substitute the values

m=\frac{8-7}{11-r}

m=\frac{1}{11-r}

Remember that

m=-\frac{1}{5}

equate the equations

\frac{1}{11-r}=-\frac{1}{5}

solve for r

Multiply in cross

-(11-r)=5\\r-11=5\\r=11+5\\r=16

4 0
3 years ago
PLZ SOMEONE HELP ME ON THIS<br><br>THX ~ BRAiNLiEST AVAiLABLE<br>ASAP HURRYYYY !!!!!!!!!!
VARVARA [1.3K]
Function 2 has the lowest average rate of change.

4 0
4 years ago
Simplify.
pishuonlain [190]

Answer:

16+4(q+11)+10q  simplified is 14q+60

Showed work for this: 16+4(q+11)+10q --> then we expand (q+11) due to PEMDAS, this will get us 16+4q+44+10q --> we do that then we get 14q+60

For the other ones: They cannot be simplified further these would be "factored" or "cannot simplify further" if you are writing on paper.

5 0
3 years ago
Read 2 more answers
Need answer quickly! thank you in advance!
anyanavicka [17]

Answer:

b)(b²-a²)

Step-by-step explanation:

a cotθ + b cosecθ =p

b cotθ + a cosecθ =q

Now,

p²- q²

=(a cotθ + b cosecθ)² - (b cotθ + a cosecθ)²     [a²-b²=(a+b)(a-b)]

=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]

={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}

={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}

=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)

=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)        

= (cot²θ-cosec²θ) (a²-b²)                                 [(a+b) (a-b)= (a²-b²)]

= -1 . (a²-b²)                               [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]

=(b²-a²)

6 0
4 years ago
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