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3 years ago

What is the following product? square root 30 times square root 10

Mathematics

1 answer:

egoroff_w [7]3 years ago

4 0

Answer:

D. 10 square root 3 is your answer

Step-by-step explanation:

Here is what you do.

square root 30 = 3 x 2 x 5

square root 10 = 2 x 5

Add them together.

3 x 2 x 2 x 5 x 5

3 x 4 x 25.

4 and 25 can come out of the square root.

2 x 5 = 10

10 square root 3 is your answer.

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Which of the following equations have no solutions? Choose all answers that apply:

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Answer:

Step-by-step explanation:

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all the rest equations will give an answer

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3 years ago

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For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.

vampirchik [111]

Answer:

The angle between the given vectors u and v is $\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Step-by-step explanation:

Given vectors are $\overrightarrow{u}=(3,4)$ and $\overrightarrow{v}=(1,3)$

Now compute the dot product of u and v:

$\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)$

$=(3)(1)+(4)(3)$

$=3+12$

$=15$

Now find the magnitude of u and v:

$|\overrightarrow{u}|=\sqrt{3^2+4^2}$

$=\sqrt{9+16}$

$=\sqrt{25}$

$=5$

$|\overrightarrow{u}|=5$

$|\overrightarrow{v}|=\sqrt{1^2+3^2}$

$=\sqrt{1+9}$

$=\sqrt{10}$

$|\overrightarrow{v}|=\sqrt{10}$

To find the angle between the given vectors

$\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta$

$\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]$

$=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]$

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

Therefore the angle between the vectors u and v is

$\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]$

3 0

3 years ago

- Cindy spent $6 on her meal. She spent $4

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Answer:

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Step-by-step explanation:

6 0

4 years ago

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The rate is 320 feet per hour, 320 feethour . The hiking team descended the mountain from 1 pm to 5 pm. The net change is a ____

deff fn [24]

Answer:

The correct answer is "decrease, 1,280 feet".

Step-by-step explanation:

The given values are:

Rate or speed,

= 320 feet per hour

1 pm to 5 pm means,

t = 5 - 1

= 4 hours

Now,

The net change in distance will be:

⇒ $\Delta D=-320\times 4 \ feet$

⇒ $=-1280 \ feet$

Thus the above is the correct approach.

8 0

3 years ago

Done yay !!!!!!!!!!!!!!

Alex

Adjacent, cosine again.

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3 years ago

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