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pychu [463]
3 years ago
12

What is the following product? square root 30 times square root 10

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

D. 10 square root 3 is your answer

Step-by-step explanation:

Here is what you do.

<em>square root 30 = 3 x 2 x 5 </em>

<em>square root 10 = 2 x 5</em>

Add them together.

<em>3 x 2 x 2 x 5 x 5 </em>

<em>3 x 4 x 25.</em>

4 and 25 can come out of the square root.

<em>2 x 5 = 10</em>

10 square root 3 is your answer.

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
Evaluate 2/ 3 ÷ 4 /5 Give your answer as a fraction in its simplest form.
gulaghasi [49]

Step-by-step explanation:

<u>Our problem:</u>

\frac{2}{3}   \div  \frac{4}{5}  = unknown

How to solve?

Find the reciprocal (opposite) of 4/5, then multiply. Simplify if necessary.

<u>Find the reciprocal:</u>

\frac{2}{3}  \times  \frac{5}{4}  = unknown

<u>Multiply:</u>

\frac{2}{3}  \times  \frac{5}{4}  =  \frac{10}{12}

<u>Simplify:</u>

\frac{10 \div 2}{12 \div 2}  =  \frac{5}{6}

5/6 is your answer.

7 0
2 years ago
Solve by simplifying the problem. There are 18 students in Mr. Alvarez’s art class. Throughout the year, every student must pair
Alla [95]
We are given with an 18 student class that is working a project worked by pairs. Each pair works on a project. In this case, there are 9 teams of 2 individuals working on a single project. Hence for a year or school year, there are 9 projects accomplished each time.
5 0
3 years ago
Item 1 The value of a car is $23,000. It loses 11.1% of its value every year. Find the approximate monthly decrease in value. Ro
IrinaK [193]

Answer:

<h2>$212.8</h2>

Step-by-step explanation:

If the car loses 11.1% per year, we need to calculate how much money is that:

23,000\frac{11.1}{100} = 2,553.; this value is the lost per year.

Now, in order to calculate this loss per month, we divide it by 12:

\frac{2553}{12} =212.75

Hence, the monthly value decrease is $212.8, rounding it to the tenth.

7 0
3 years ago
HELP PLS! A boat is heading towards a lighthouse, whose beacon-light is 102 feet above the water. From point AA, the boat’s crew
KatRina [158]

Answer:

Distance from point AA to point BB = 189.3 feet

Step-by-step explanation:

Let the distance from point AA to the base of the lighthouse be represented by x, and the distance from point BB to the base of the lighthouse be represented by y. So that;

distance from point AA to point BB = x - y

To determine the value of x, applying the required trigonometric function;

Tan θ = \frac{opposite}{sdjacent}

Tan 13 = \frac{102}{x}

x = \frac{102}{Tan 13}

  = 441.81 feet

x = 441.8 feet

To determine the value of y;

Tan 22 = \frac{102}{y}

y = \frac{102}{Tan 22}

  = 252.46

y = 252.5 feet

Thus,

distance from point AA to point BB = 441.8 - 252.5

                                                           = 189.3 feet

5 0
3 years ago
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